The Theory on the Encoding of C2
<f108v.8,+P0> ysheedy.okeedy.oteedy.qokeedy.okeedy.okeedy.chedal.okar.qoteedar.oty
The section under consideration is:
oteedy.qokeedy.okeedy.okeedy.chedal
Vowel Bridge Model (VBM) vowels are:
oteedy.qokeedy = y.qo
qokeedy.okeedy = y.o
okeedy.okeedy = y.o
okeedy.chedal = y.ch
Decomposition:
y.qo | k.eed | y.o | k.eed | y.o | k.eed | y.ch
With the test values:
y.qo = e
y.o = e (for testing)
y.ch = e (for testing)
k (C1) = n
eed (C2) = n (for testing)
the result is:
e | nn | e | nn | e | nn | e
so:
ennen . nenne
Where y.ch could also be another vowel, e.g., a.
ennen. nenna.. nenna could then be something like "nenn" a "call a” etc., so there are many possibilities.
The first C2 Consonant is interesting; one would actually think it should be an n, just like the others.
But there is a peculiarity in the VMS: our C2 (i.e., slot 3 of the tokens) shows an extremely strong connection with the final glyph of the tokens, the well known “dy” effect. In the VBM, this is explained as follows:
C2 and the vowel bigram are together part of one cipher. This means the left part of the vowel bigram indicates the link, and the right part specifies which variant of C2 is used. It sounds complicated, but it’s actually quite simple.
Example: C2= eed // (hypothesis)
eed is n when y.o appears next to it as e.
eed is k when y.qo appears next to it as e.
And this also applies to other C2 values like ed, eod, etc... Two markers here each provide the information on how C2 is read. That’s all it needs to be, but it turns out to be more—though I haven’t figured that part out yet. These two patterns, however, seem to hold true.
In this respect, our chain (in the e variation) yields:
MHG = "kennen, nenne" one of many possible sentences: "die es kennen, nennen es rot.."
English: "know it, call it" one of many possible sentences: " Those who know it call it red..."
What makes this theory so unique: It explains why so few forms repeat constantly. They may do so because different consonants are essentially encoded with the same glyphs.
As beautiful as all this is, and as perfectly as it fits the structure of the VMS, it naturally makes decipherment not easier.
Overview:
We have three levels in the stream with different encodings
1. The vowel bridge. Homophonic encodings of vowels.
2. C1 Simple substitution.
3. C2 moves toward polyphonic encoding; the simple substitution of C2 is distinguished by two or more types of vowel bridges.
I know this seems to looks very complicated, but as I said, it’s really very simple.
<f108v.8,+P0> ysheedy.okeedy.oteedy.qokeedy.okeedy.okeedy.chedal.okar.qoteedar.oty
The section under consideration is:
oteedy.qokeedy.okeedy.okeedy.chedal
Vowel Bridge Model (VBM) vowels are:
oteedy.qokeedy = y.qo
qokeedy.okeedy = y.o
okeedy.okeedy = y.o
okeedy.chedal = y.ch
Decomposition:
y.qo | k.eed | y.o | k.eed | y.o | k.eed | y.ch
With the test values:
y.qo = e
y.o = e (for testing)
y.ch = e (for testing)
k (C1) = n
eed (C2) = n (for testing)
the result is:
e | nn | e | nn | e | nn | e
so:
ennen . nenne
Where y.ch could also be another vowel, e.g., a.
ennen. nenna.. nenna could then be something like "nenn" a "call a” etc., so there are many possibilities.
The first C2 Consonant is interesting; one would actually think it should be an n, just like the others.
But there is a peculiarity in the VMS: our C2 (i.e., slot 3 of the tokens) shows an extremely strong connection with the final glyph of the tokens, the well known “dy” effect. In the VBM, this is explained as follows:
C2 and the vowel bigram are together part of one cipher. This means the left part of the vowel bigram indicates the link, and the right part specifies which variant of C2 is used. It sounds complicated, but it’s actually quite simple.
Example: C2= eed // (hypothesis)
eed is n when y.o appears next to it as e.
eed is k when y.qo appears next to it as e.
And this also applies to other C2 values like ed, eod, etc... Two markers here each provide the information on how C2 is read. That’s all it needs to be, but it turns out to be more—though I haven’t figured that part out yet. These two patterns, however, seem to hold true.
In this respect, our chain (in the e variation) yields:
MHG = "kennen, nenne" one of many possible sentences: "die es kennen, nennen es rot.."
English: "know it, call it" one of many possible sentences: " Those who know it call it red..."
What makes this theory so unique: It explains why so few forms repeat constantly. They may do so because different consonants are essentially encoded with the same glyphs.
As beautiful as all this is, and as perfectly as it fits the structure of the VMS, it naturally makes decipherment not easier.
Overview:
We have three levels in the stream with different encodings
1. The vowel bridge. Homophonic encodings of vowels.
2. C1 Simple substitution.
3. C2 moves toward polyphonic encoding; the simple substitution of C2 is distinguished by two or more types of vowel bridges.
I know this seems to looks very complicated, but as I said, it’s really very simple.