Voynich anagramming

[Torsten]

Yes, for every case there is the "dominating" anagram. Curious...

Examples without a "dominating" anagram exists:

%coverage wordlength sortedletters [anagrams] (counts)
0.10821939 5 alor [arol, olar, oral, alor, loar] (12, 11, 10, 7, 1)
0.023755478 2 as [as, sa] (5, 4)
0.007918492 3 aadr [daar, dara, adar] (1, 1, 1)

However, in the case of the high frequency examples there is always only one "dominating" word type.