Ruby's Greek Thread

[Oscroft]

I believe that the similarity is between EVA k and latin "m". Then μ is the greek letter that corresponds to latin m.

And the problem with that is that the Voynichese letter that corresponds with EVA "k" (which might or might not correspond with the Latin "m") does not itself correspond with the Latin "m" (unless by pure chance, as nobody knows the actual Latin equivalent of any Voynichese letter - some of them were named in EVA as they had apparent similar written forms to Latin letters, but that's completely arbitrary and absolutely does not imply a Voynichese-to-Latin equivalence).

The "k" (or "m") is the result of a single substitution cipher, and therefore carries none of the phonetic properties of the plaintext letter. It's possible that I'm the one misunderstanding something here, but it seems painfully simple to me - though absolutely impossible to get our would-be Voynich detective to understand.