My Solution – Abbreviated Middle High German

[oshfdk]

This was exactly what I was doing: identifying repetitions, determining the meanings of words standing next to each other, checking contexts and weighing up possible readings. Whether you apply this approach to Middle High German or – like many before me – to other languages, makes no fundamental difference at first. Each language has a limited vocabulary and recurring patterns.

Here are some strong patterns from various sections of the manuscript. Could you show your method on a few of them? Why do certain words repeat up to five times in a row with minimal variations?

<f8v.8,+P0>       okcholksh.<->chol.chol.chol.cthaiin.dain
<f15v.5,+P0>      otchor.chor.chor.ytchor.cthy.s
<f15v.9,+P0>      otchol,octhol.chol.chol.chody.kan
<f40r.9,+P0>      taiin.ol.olaiin.or.<->dain.okaiin.okaiin.okaiin.daram
<f44v.11,+P0>     okal.chol.chol.choky.okaiin.cthy.otal
<f66r.54,+P0>     qokeeody.qokeody.qokeody.qokar.sheky.qokeeody.okedy.kodary
<f75r.13,+P0>     pchedy.keedy.qokedy.<->qokedy.qokedy.qokedy.qokain.olshedy
<f75r.38,+P0>     qokeedy.qokeedy.qokedy.qokedy.qokeedy.ldy
<f79r.18,+P0>     solor.olshey.qokaiin.chey.qokain.otain.otain.otal,ol,dam
<f79v.19,+P0>     ykail,shy.qolar,shey.qokedy.qokedy.qokedy.dar.olkain.cham
<f89r2.8,+P0>     tol.daiin.daiin.daiinody.qokeey.cheoldy.qody.cheor.sain.daiin.oky.cheody.cheoky<$>
<f99v.38,+P0>     ol.cheey.qokeol.okeol.okeol.shokol.<->ykey
<f102v2.36,+P0>   okeeor.cheey.okeey.sor.eeey.okey.okey.okeey.qokeor
<f107v.47,+P0>    y,cheey.qokeey.okeoteey.qokey.qokey.qokeey.daiin.y.okeey.odain
<f108r.49,+P0>    oteedy.lchedy.qokeedy.qokeedy.qokeo.lchedy.qokey.qokeey.lkedy.lkedy
<f108v.8,+P0>     ysheedy.okeedy.oteedy.qokeedy.okeedy.okeedy.chedal.okar.qoteedar.oty
<f108v.40,+P0>    daiin.sheeal.qokeedy.qokeedy.qokeedy.qotey.qokeey.qokeey.otedy,qotaiin