19-04-2021, 07:13 PM
I can add a few statistical details about the [chory] = "YORK/#ROY" word in the center ring of text on the You are not allowed to view links. Register or Login to view. House of York imagery page:
It is true that I made the adjustment to allow EVA [o] to represent Middle English "o" as well as "ou"/"u". However, I also note that the only alternative possibility for a Voynich word to represent "YORK/#ROY", even according to my adjusted correspondence system, would be [chairy], but this word does not occur at all in the entire ms text.
Further, [chory] itself only occurs 12 times in the entire ms text. Also, the center ring of text on You are not allowed to view links. Register or Login to view. only has 10 words in it. I have calculated the exact probability that a word that occurs 12 times in a 37886-word text (the entire ms text) would happen to occur in that particular ring of 10 words due to random chance:
1 - [(37886-10)!*(37886-12)! / (37886!*(37886-22)!)] = 0.003163...
Thus, since there is only a 0.003163 probability that this particular word occurred in this particular place in the ms due to random chance, one may argue that there is a 99.68% probability that this occurrence is not due to random chance.
Geoffrey
It is true that I made the adjustment to allow EVA [o] to represent Middle English "o" as well as "ou"/"u". However, I also note that the only alternative possibility for a Voynich word to represent "YORK/#ROY", even according to my adjusted correspondence system, would be [chairy], but this word does not occur at all in the entire ms text.
Further, [chory] itself only occurs 12 times in the entire ms text. Also, the center ring of text on You are not allowed to view links. Register or Login to view. only has 10 words in it. I have calculated the exact probability that a word that occurs 12 times in a 37886-word text (the entire ms text) would happen to occur in that particular ring of 10 words due to random chance:
1 - [(37886-10)!*(37886-12)! / (37886!*(37886-22)!)] = 0.003163...
Thus, since there is only a 0.003163 probability that this particular word occurred in this particular place in the ms due to random chance, one may argue that there is a 99.68% probability that this occurrence is not due to random chance.
Geoffrey