Et littĕris multōrum et sermōne omnium perfertur ad me incredibĭlem tuam virtūtem et fortitudĭnem esse teque nec anĭmi nec corpŏris laborĭbus defatigāri. Me misĕrum! Te, ista virtūte, fide, probitāte, humanitāte2 in tantas aerumnas propte
ch a /// ch ch eor oiin dan or or a /// chor chor ch oiin o daiin daiin dan /// ch a /// eor oiin o oke daiin a a /// chor o oke daiin daiin or /// chor ch oiin oiin oiin qo an a a /// ok y /// daiin a /// oiin oke daiin dan or or or a a ok iin in /// chor ch daiin y /// chor chor ch ch oiin daiin or a /// ch a /// chor ch ch oiin o oke daiin or or an a ok /// eor eor a a /// chor ch cph a a /// oke a iin /// oke daiin or or y /// oke a iin /// eor oiin oiin q o or iin /// chor eor oiin o dan or in in y /// ch oiin or or ain an a ok y y /// daiin a /// chor eor oiin daiin daiin or a /// ch a /// ch eor or y /// chor chor ch ch oiin or a /// or an a ok /// ch ch oiin q or a in y /// chor ch ch oke daiin or aiin a n y /// oke or /// ch ch eor oke y y /// chor eor oiin oke daiin a n y /// ch oiin oiin qo q a /// daiin a /// eor eor oke or or or a ok iin
In the case of Latin, there are a lot of repetitions.
We will add nulls (unfortunately, they cannot be highlighted in this font, so you will identify them in special cases by comparing them with the original text):
cha /// char cheor oiin dan chor chor a /// chor chor choiin o daiin daiin ydan / cha / cheor choiin cho okey daiin g* / chor qokeor daiin daiin / chor choiin oiin oiin qo s* / oky / daiin am / oiin okedaiin dan chor oiin* okaiin in / chor chy daiin / chor chor choiin chodaiin otey* / cha / chor chy choiin okeodaiin chor chor chan okar / cheor cheor g* / chor chcphy g* / okeaiin / okedaiin or or y / okeaiin / cheor choiin oiin qo oraiin / chor cheor choiin odan dor* / choiin or or dain dan oky chay / daiin a / chor cheor oiin daiin daiin or dy / cha / cheor or y / chor chor cha chor oiin / okaor dan / chy choiin qo oraiin / chor ytchy chdaiin okeor aiin dy n / okeor / chy cheor okey yky / chor cheor oiin okedaiin ain / choiin oiin qoky qoky am / daiin ar / cheor yteor okeor or or okaiin
*The last e can be turned into a g;
an + a + a = s (VI + V + V = XVI);
or + a = ote (IX + V = XIV); y is a null
in + in + y = d (II + II + I = V);
As @oshfdk says, deciphering this text is a real headache. In fact, I agree with him. But I believe that if there are hints in the text that immediately reveal certain frequent positions (for example, to quickly recognize addition, etc.), then this process will be faster.
Some of the complications and additions of zeros are repeated in the text, so it is possible that the author has compiled a list of clues to the cipher that allows you to quickly arrive at the numbers themselves.
Yes, decryption is complicated, but it can be simplified...
ch a /// ch ch eor oiin dan or or a /// chor chor ch oiin o daiin daiin dan /// ch a /// eor oiin o oke daiin a a /// chor o oke daiin daiin or /// chor ch oiin oiin oiin qo an a a /// ok y /// daiin a /// oiin oke daiin dan or or or a a ok iin in /// chor ch daiin y /// chor chor ch ch oiin daiin or a /// ch a /// chor ch ch oiin o oke daiin or or an a ok /// eor eor a a /// chor ch cph a a /// oke a iin /// oke daiin or or y /// oke a iin /// eor oiin oiin q o or iin /// chor eor oiin o dan or in in y /// ch oiin or or ain an a ok y y /// daiin a /// chor eor oiin daiin daiin or a /// ch a /// ch eor or y /// chor chor ch ch oiin or a /// or an a ok /// ch ch oiin q or a in y /// chor ch ch oke daiin or aiin a n y /// oke or /// ch ch eor oke y y /// chor eor oiin oke daiin a n y /// ch oiin oiin qo q a /// daiin a /// eor eor oke or or or a ok iin
In the case of Latin, there are a lot of repetitions.
We will add nulls (unfortunately, they cannot be highlighted in this font, so you will identify them in special cases by comparing them with the original text):
cha /// char cheor oiin dan chor chor a /// chor chor choiin o daiin daiin ydan / cha / cheor choiin cho okey daiin g* / chor qokeor daiin daiin / chor choiin oiin oiin qo s* / oky / daiin am / oiin okedaiin dan chor oiin* okaiin in / chor chy daiin / chor chor choiin chodaiin otey* / cha / chor chy choiin okeodaiin chor chor chan okar / cheor cheor g* / chor chcphy g* / okeaiin / okedaiin or or y / okeaiin / cheor choiin oiin qo oraiin / chor cheor choiin odan dor* / choiin or or dain dan oky chay / daiin a / chor cheor oiin daiin daiin or dy / cha / cheor or y / chor chor cha chor oiin / okaor dan / chy choiin qo oraiin / chor ytchy chdaiin okeor aiin dy n / okeor / chy cheor okey yky / chor cheor oiin okedaiin ain / choiin oiin qoky qoky am / daiin ar / cheor yteor okeor or or okaiin
*The last e can be turned into a g;
an + a + a = s (VI + V + V = XVI);
or + a = ote (IX + V = XIV); y is a null
in + in + y = d (II + II + I = V);
As @oshfdk says, deciphering this text is a real headache. In fact, I agree with him. But I believe that if there are hints in the text that immediately reveal certain frequent positions (for example, to quickly recognize addition, etc.), then this process will be faster.
Some of the complications and additions of zeros are repeated in the text, so it is possible that the author has compiled a list of clues to the cipher that allows you to quickly arrive at the numbers themselves.
Yes, decryption is complicated, but it can be simplified...