Voynichese is a numeric cipher?

[ololololo]

Can you actually read this cipher off the page?

I suppose so, since I created this cipher  

I mean, can a person who spent some time using this cipher look at "chor shoiin okey daiin daiin chan ches / chor sheor qokeol dy" and after thinking for a few seconds at most get the Latin original?

I don't think the decoding is difficult in itself. First, you just need to decode all the combinations you have, getting numbers. Then, you convert all the numbers into letters using the alphabet. To begin with, you can solve anagrams that do not contain nulls or addition to get clues for the next words.
In the case of qokey or dy, you check: in the case of qokey, you translate it into o oke and see if it fits. If it doesn't, then the k in qokey will be a null. In the case of dy, you translate it into VI and see if it fits. If it doesn't, then it's a null.
Solving such distorted anagrams shouldn't be that difficult, I suppose. You'll just end up with extra letters that are easy to distinguish from the real ones.

I have no idea how your cipher works exactly, but the description looks insanely complicated.

Substitution, anagrams, and number substitution. To encrypt and decrypt text, you need at least a complete second alphabet with all the options for numbers.

It looks like it might take more than a minute to read just a single phrase.

Perhaps... But not ten minutes or an hour. The only difficulty will be in reading the anagrams.

Regarding my texts... This is an encrypted excerpt of Lorem ipsum, which I don't think is suitable for demonstration of decryption.