Labyrinthinesecurity > 05-05-2026, 04:24 PM
(05-05-2026, 04:14 PM)Grove Wrote: You are not allowed to view links. Register or Login to view.Isn’t that cho mapped to A opposite of what you said here:
all traditionally classified as Currier A because they fall in the f1-f57 range. But their text is E-dominant, and their plant illustrations show B-type features (daisies, grass, root platforms, unidirectional leaves). Conversely, f87r, f90r, f93v, and You are not allowed to view links. Register or Login to view. are traditionally Currier B, but their text is O-dominant and their plants show A-type features (stem-root lines, A-type flowers and calyxes).
Isn’t that cho mapped to A opposite of what you said here:
all traditionally classified as Currier A because they fall in the f1-f57 range. But their text is E-dominant, and their plant illustrations show B-type features (daisies, grass, root platforms, unidirectional leaves). Conversely, f87r, f90r, f93v, and You are not allowed to view links. Register or Login to view. are traditionally Currier B, but their text is O-dominant and their plants show A-type features (stem-root lines, A-type flowers and calyxes).
Ahh, I see I misunderstood gut have misread that. So che dominant is your B and che is A.
dashstofsk > 05-05-2026, 04:34 PM
(05-05-2026, 03:03 PM)Labyrinthinesecurity Wrote: You are not allowed to view links. Register or Login to view.87v and 90v (v1+v2)
nablator > 05-05-2026, 07:08 PM
(05-05-2026, 03:59 PM)Labyrinthinesecurity Wrote: You are not allowed to view links. Register or Login to view.the cho counter sums both cho and sho. Likewise for the che counter: it sums both che and she.
f2r: 17 cho+sho, 6 che+she → r_cho = 0.739 (73.9% cho) → Language A
f2v: 21 cho+sho, 4 che+she → r_cho = 0.840 (84.0% cho) → Language A
Labyrinthinesecurity > 05-05-2026, 08:01 PM
(05-05-2026, 07:08 PM)nablator Wrote: You are not allowed to view links. Register or Login to view.(05-05-2026, 03:59 PM)Labyrinthinesecurity Wrote: You are not allowed to view links. Register or Login to view.the cho counter sums both cho and sho. Likewise for the che counter: it sums both che and she.
f2r: 17 cho+sho, 6 che+she → r_cho = 0.739 (73.9% cho) → Language A
f2v: 21 cho+sho, 4 che+she → r_cho = 0.840 (84.0% cho) → Language A
In the RF1b-e.txt file (from your You are not allowed to view links. Register or Login to view.) I have:
f2r: 18 cho+sho, 6 che+she
f2v: 24 cho+sho, 7 che+she
[BTW RenéZ might have updated a few lines without changing the version number, you don't have the latest.]
These counts are produced by the switch.py script.
c = classify_word_cho(w)
if c == 'cho':
cho_c += 1
elif c == 'che':
che_c += 1
...
def classify_word_cho(word):
...
if has_cho and not has_che:
return 'cho'
elif has_che and not has_cho:
return 'che'
return None
For example f2v: I see 7 che+she.
But cheopchor and chotchey are classified as None, so it should be 5 not 4 che+she. I must be missing something...
>>> classify_word_cho('cheor')
'che'
>>> classify_word_cho('sshey')
'che'
>>> classify_word_cho('chees')
'che'
>>> classify_word_cho('cheaiin')
'che'
>>> classify_word_cho('cheol')
'che'
nablator > 05-05-2026, 08:38 PM
Labyrinthinesecurity > 05-05-2026, 08:39 PM
(05-05-2026, 08:01 PM)Labyrinthinesecurity Wrote: You are not allowed to view links. Register or Login to view.(05-05-2026, 07:08 PM)nablator Wrote: You are not allowed to view links. Register or Login to view.(05-05-2026, 03:59 PM)Labyrinthinesecurity Wrote: You are not allowed to view links. Register or Login to view.the cho counter sums both cho and sho. Likewise for the che counter: it sums both che and she.
f2r: 17 cho+sho, 6 che+she → r_cho = 0.739 (73.9% cho) → Language A
f2v: 21 cho+sho, 4 che+she → r_cho = 0.840 (84.0% cho) → Language A
In the RF1b-e.txt file (from your You are not allowed to view links. Register or Login to view.) I have:
f2r: 18 cho+sho, 6 che+she
f2v: 24 cho+sho, 7 che+she
[BTW RenéZ might have updated a few lines without changing the version number, you don't have the latest.]
These counts are produced by the switch.py script.
c = classify_word_cho(w)
if c == 'cho':
cho_c += 1
elif c == 'che':
che_c += 1
...
def classify_word_cho(word):
...
if has_cho and not has_che:
return 'cho'
elif has_che and not has_cho:
return 'che'
return None
For example f2v: I see 7 che+she.
But cheopchor and chotchey are classified as None, so it should be 5 not 4 che+she. I must be missing something...
>>> classify_word_cho('cheor')
'che'
>>> classify_word_cho('sshey')
'che'
>>> classify_word_cho('chees')
'che'
>>> classify_word_cho('cheaiin')
'che'
>>> classify_word_cho('cheol')
'che'
run the script as is using the transliteration file as input: any error?
nablator > 05-05-2026, 08:45 PM
(05-05-2026, 08:39 PM)Labyrinthinesecurity Wrote: You are not allowed to view links. Register or Login to view.I'm not familiar with the intricacies of the STA standard, will have to check the parsing and the contents of f2 when I have access to a computer.
Labyrinthinesecurity > 05-05-2026, 10:04 PM
nablator dateline='[url=tel:1778010306' Wrote: You are not allowed to view links. Register or Login to view.1778010306[/url]']
Labyrinthinesecurity dateline='[url=tel:1778009963' Wrote: You are not allowed to view links. Register or Login to view.1778009963[/url]']
I'm not familiar with the intricacies of the STA standard, will have to check the parsing and the contents of f2 when I have access to a computer.
It's IVTFF.
"<->" are illustrations that separate words, they should be processed like ".", not ignored if you want to extract words.
"{...}" for example "{cko}" are unusual connected glyphs (other than the most usual 'benched' combinations starting with c/s and ending with h): they should not be removed.
Labyrinthinesecurity > Yesterday, 08:11 AM