Deconstructing the VMS : A positionless ledger (part 1)
#45
(01-09-2026, 09:02 PM)Jorge_Stolfi wrote: You are not allowed to view links. Register or Login to view.
(01-09-2026, 07:12 PM)Dunsel wrote: You are not allowed to view links. Register or Login to view.Do you have a link to your most current transcription?

The one I am using is You are not allowed to view links. Register or Login to view.

It is not quite in Rene's IVTFF format, so you will have to process it a bit before it is accepted by Rene's tools.  Mostly, it has no page header lines (you would have to copy them from Rene's), and instead of Rene's position codes "l+", "l0", etc, I use "«", "=", or "»" to indicate the position of the line's start or end relative to the corresponding rail (ideal margin line).  I also use "f85v2" instead of "fRos" for the page number of the Rosettes fold-out.

Actually my own transcription (code ";U") is only 80% complete; the other 20% are copied from Rene's transcription (code ";Z").  The Starred Parags section is all ";U".

All the best, --stolfi

So for the type work I do, I pretty much ignore most tags. I'm only concerned with the text and it's data.  So, for your transcription I did the following:

"." - solid word break
"," - possible word break
"-" - major text break

For all of those, I converted them to spaces.  If that's not the intended interpretation of the breaks, let me know and I can rework it.

? - splats.  While I could make some educated guesses as to what splats might be, I strip any word that contains even 1 splat.  I'm interested in letter transition accuracy which shouldn't change with splat removal.

All of your other tags, stripped.

You also use b, j, u and v.  I included them.  In this ledger build I used words length 3+ and considered rare words to be count 3-.  Your b only occurs as a suffix therefore, it has no midfix or suffixes that appear after it. And your u has only one occurrence as tauiin where it's a midfix so it only has a rare i as a midfix that follows it.  All other occurrences are as suffix.  That's why those two letter rows will look a bit empty.

Also for my work, I've created a 'mappings' JSON file that I work with.  It basically breaks the Voynich down into it's unique words and then records a good bit of data about each word. I've included it for you to look over.


With gallows stripped

PrefixCore midfixRare midfixSuffix
ai, l, ra, c, ch, d, e, g, j, m, n, o, s, sh, u, x, ych, d, e, g, i, j, l, m, n, o, r, s, y
oa, ch, d, e, i, l, o, r, s, shc, g, h, j, m, q, x, ya, c, ch, d, e, g, j, l, m, n, o, r, s, sh, y
da, ch, e, o, shc, d, g, i, l, r, s, x, ya, c, ch, d, e, g, l, m, o, r, s, sh, u, y
la, ch, d, o, shc, e, g, i, l, q, r, s, x, ya, c, ch, d, e, g, l, m, o, r, s, sh, y
cha, d, e, oc, ch, g, h, i, l, r, s, sh, ya, b, c, ch, d, e, g, h, i, l, m, o, r, s, sh, x, y
sha, ch, d, e, oc, h, l, s, sh, x, ya, d, e, l, o, r, s, x, y
ea, d, e, o, sc, ch, g, i, l, r, sh, ya, b, c, ch, d, e, g, l, m, n, o, r, s, sh, u, y
ya, ch, d, she, h, i, l, o, q, r, s, ya, ch, d, e, g, l, m, o, r, s, sh, u, y
sa, ch, o, shd, e, l, q, r, s, ya, ch, d, e, g, i, l, m, n, o, s, y
ra, ch, i, o, shd, e, l, x, ya, ch, d, e, g, i, l, m, o, s, y
qoa, ch, e, r, s, ye, o
hnonea, ch, d, e, h, od, o, y
mnonea, ch, d, o, shd, g, o, y
nnonea, ch, d, o, sh, yd, e, g, l, o, r, s, y
gnoneao, s, y
xad, oy
cnonea, ch, e, o, so, y
id, i, n, ra, c, ch, e, j, l, m, o, s, shch, d, g, i, l, m, n, r, s, x, y
bnonenonenone
jnonea, shy
unoneinone



With gallows retained

PrefixCore midfixRare midfixSuffix
ai, l, ra, c, ch, d, e, f, g, j, k, m, n, o, p, s, sh, t, u, x, yd, e, g, i, j, l, m, n, o, p, r, s, y
oa, ch, d, e, i, l, o, r, s, shc, f, g, h, j, k, m, p, q, t, x, ya, c, ch, d, e, f, g, j, k, l, m, n, o, p, r, s, sh, t, y
da, ch, e, o, shc, d, g, i, k, l, p, r, s, t, x, ya, ch, d, e, g, l, m, o, r, s, sh, u, y
la, ch, d, o, shc, e, f, g, k, l, p, q, r, s, t, x, ya, ch, d, f, g, k, l, m, o, p, r, s, sh, t, y
cha, d, e, oc, ch, f, g, h, i, k, l, p, r, s, sh, t, ya, b, d, e, g, i, k, l, m, o, p, r, s, sh, t, x, y
sha, ch, d, e, oc, f, h, k, l, s, sh, t, x, ya, d, e, l, o, r, s, x, y
ea, d, e, o, sc, ch, f, g, i, k, l, p, r, sh, t, ya, b, ch, d, e, f, g, k, l, m, n, o, p, r, s, sh, t, u, y
ya, ch, d, shc, e, f, h, k, l, o, p, q, r, s, td, f, g, k, l, m, o, r, s, t
sa, ch, o, shc, d, e, f, k, l, p, q, r, s, t, ya, d, e, g, i, l, m, n, o, s, y
ra, ch, i, o, shc, d, e, f, k, l, p, x, ya, ch, d, e, g, i, k, l, m, o, s, y
qoa, c, ch, e, f, k, p, r, s, yo
hnonea, c, ch, d, e, h, k, l, o, r, s, t, yd, e, h, o, s, y
mnonea, ch, d, o, shd, g, o, y
nnonea, ch, d, k, o, sh, yd, e, g, l, o, r, s, y
gnoneao, s, y
xad, oy
cnonec, f, k, p, s, tf, t, y
id, i, n, ra, c, ch, e, f, j, k, l, m, o, p, s, sh, tch, d, g, i, l, m, n, p, r, s, x, y
bnonenonenone
fnonea, ch, d, e, h, o, s, sh, yo, y
jnonea, ky
knonea, c, ch, d, e, h, i, l, o, s, sh, ya, ch, d, e, g, h, l, o, r, sh, u, y
pnonea, ch, d, e, h, o, p, s, sh, ya, ch, o, s, y
tnonea, c, ch, d, e, h, i, k, l, o, sh, ya, ch, e, h, l, o, s, sh, y
unoneinone


Files:


.zip   mappings_Stolfi_join25e1.zip (Size: 805.55 KB / Downloads: 2)

.zip   Stolfi_join25e1_stripped_hapax.zip (Size: 1.84 MB / Downloads: 2)

I wasn't able to attach the full gallows file as even zipped it exceeded the 2mb limit.  I got it down to size with other formats but the forum rejected them.  Sorry.

*edit* I noticed something unusual in your transcription, the C row.
  • C has no core transitions in either ledger.
  • In the intact ledger, four of its six rare midfix followers are gallows: F, K, P, T.
  • After gallows stripping, all four disappear and are replaced by A, CH, E, O.
  • The only rare midfix transition surviving unchanged is C→S.
  • Suffix changes similarly: intact F,T,Y becomes stripped O,Y. Only Y survives.

With gallows intact, standalone c mostly transitions into f/k/p/t. In 98.1% of those token occurrences, the gallows is immediately followed by h, so the pattern is: c + gallows + h. When the gallows is stripped, those forms collapse to atomic ch , which is why the c row changes so dramatically.

There are 217 c-initial types in the transcription, 896 tokens, and every one has a gallows. After stripping, 871 of those 896 tokens become ch-initial. Outside gallows words, I find only one minimum-length-3 word in your transcription containing standalone c: ocsesy.

So the main result is in your transcription, standalone c is overwhelmingly tied to gallows constructions, especially c + gallows + h.
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RE: Deconstructing the VMS : A positionless ledger (part 1) - by Dunsel - 01-09-2026, 10:33 PM

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