Proof for [i] and [n] equivalence?

[farmerjohn]

I haven't found more relevant thread to discuss ai-family glyphs, so I'll post it here.
Two ideas concerning ai-glyphs nature:

1) They are vowels and n is an empty symbol. That's pretty obvious. If voynichese is some vowelless language, then we still need vowels sometimes, to specify declension case, etc.

2) (kind of generalization of 1) - they are modifiers for the next glyph. 
Suppose there is default value for each glyph. Take for example r and let the default value be re. Now if we need some similar strings with letter r we define them by attaching some ai-modifer to r: say ar will be aer, air will be ir, aiir - ior.
Another example, say k and the default value is de  Now if we need ad, common suffix prefix in Latin, then define ak to be ad.
Now vowels are produced by taking "empty symbol" (n) and "modifying" it with ai-sequence.
This can explain why ai-sequence can appear in the middle of the word followed by n (then it's a vowel all together) or not followed by n (then it's some modification of the next symbol). Of course there are some a's at the end of the word, but this is a special position where everything changes...