13-06-2016, 05:51 PM
I have done a quick count of the repetitions in the herbal section of the revised editions of the ten words listed above with the following results when the EVA = d code is removed:
chedy 52 repetitions che/d/y chey 61 repetitions (46 Language A, 15 Language B)
I V VI
shedy 29 repetitions she/d/y shey 32 repetitions (27 Language A, 5 Language B)
I V VI
okedy 25 repetitions oke/d/y okey 8 repetitions (3 Language A, 5 Language B)
I V VI
otedy 21 repetitions ote/d/y otey 4 repetitions (2 Language A, 2 language B)
I V VI
qokedy 35 repetitions qoke/d/y qokey 7 repetitions (4 Language A, 3 Language B)
I V VI
qotedy 15 repetitions qote/d/y qotey 1 repetition (1 Language A, 0 Language B)
I V VI
ykedy 8 repetitions yke/d/y ykey 4 repetitions (2 language A, 2 Language B)
I V VI
ytedy 8 repetitions yte/d/y ytey 5 repetitions (2 Language A, 3 Language B)
I V VI
kedy 9 repetitions ke/d/y key 5 repetitions (3 language A, 2 Language B)
I V VI
tedy 8 repetitions te/d/y tey 2 repetitions (2 Language A, 0 Language B)
I V VI
If my ideas are correct, the above numbers of occurrences might mean the conversion from showing to omitting (or vice versa) the EVA = d glyph from Group V happened sometime during the writing/copying of the Language B pages. This is because there are almost no words ending in EVA = edy in Language A, only those ending in EVA = ey, while there are numerous occurrences of words ending in both EVA = edy and ey in Language B.
Is anyone following all this?
(In my larger proposed solution, this would be the difference between something like 'sorrel, one, grain' and 'sorrel, (one, understood), grain' or 'ispaghul, one, grain' and 'ispaghul, (one, understood), grain'. Notice the EVA = e in each shortened word is located where there should be a Group V code glyph, and isn't. EVA = e is not a Group V code glyph or part of a longer Group VI code. This let's the reader know there is no (required*) Group V code glyph present, therefore the number 'one' (EVA = d in Group V) is understood between the EVA = e and the EVA = y.)
This only works with Voynich words longer than two glyphs in length. For two-glyph words ending in EVA = y, the EVA = d is always understood to be present in the middle of the word. (But, since, in my proposed solution, it is a quantity and that quantity is one, it's physical presence is not really needed - and Voynich words are always the shortest strings of coded parts strung together that clearly show the meaning of each word.)
I hope I'm explaining this well enough that others can follow my chain of thought/reasoning. It doesn't seem too difficult a concept to understand, but maybe that's because I'm the one who thought of it.
If anyone has questions, I'll try to answer them.
Thank you.
Don of Tallahassee
*See my VMS deconstruction scheme for the rules for what parts are where in Voynich words and how to differentiate the parts in each word by following the deconstruction sequence.
chedy 52 repetitions che/d/y chey 61 repetitions (46 Language A, 15 Language B)
I V VI
shedy 29 repetitions she/d/y shey 32 repetitions (27 Language A, 5 Language B)
I V VI
okedy 25 repetitions oke/d/y okey 8 repetitions (3 Language A, 5 Language B)
I V VI
otedy 21 repetitions ote/d/y otey 4 repetitions (2 Language A, 2 language B)
I V VI
qokedy 35 repetitions qoke/d/y qokey 7 repetitions (4 Language A, 3 Language B)
I V VI
qotedy 15 repetitions qote/d/y qotey 1 repetition (1 Language A, 0 Language B)
I V VI
ykedy 8 repetitions yke/d/y ykey 4 repetitions (2 language A, 2 Language B)
I V VI
ytedy 8 repetitions yte/d/y ytey 5 repetitions (2 Language A, 3 Language B)
I V VI
kedy 9 repetitions ke/d/y key 5 repetitions (3 language A, 2 Language B)
I V VI
tedy 8 repetitions te/d/y tey 2 repetitions (2 Language A, 0 Language B)
I V VI
If my ideas are correct, the above numbers of occurrences might mean the conversion from showing to omitting (or vice versa) the EVA = d glyph from Group V happened sometime during the writing/copying of the Language B pages. This is because there are almost no words ending in EVA = edy in Language A, only those ending in EVA = ey, while there are numerous occurrences of words ending in both EVA = edy and ey in Language B.
Is anyone following all this?
(In my larger proposed solution, this would be the difference between something like 'sorrel, one, grain' and 'sorrel, (one, understood), grain' or 'ispaghul, one, grain' and 'ispaghul, (one, understood), grain'. Notice the EVA = e in each shortened word is located where there should be a Group V code glyph, and isn't. EVA = e is not a Group V code glyph or part of a longer Group VI code. This let's the reader know there is no (required*) Group V code glyph present, therefore the number 'one' (EVA = d in Group V) is understood between the EVA = e and the EVA = y.)
This only works with Voynich words longer than two glyphs in length. For two-glyph words ending in EVA = y, the EVA = d is always understood to be present in the middle of the word. (But, since, in my proposed solution, it is a quantity and that quantity is one, it's physical presence is not really needed - and Voynich words are always the shortest strings of coded parts strung together that clearly show the meaning of each word.)
I hope I'm explaining this well enough that others can follow my chain of thought/reasoning. It doesn't seem too difficult a concept to understand, but maybe that's because I'm the one who thought of it.
If anyone has questions, I'll try to answer them.
Thank you.
Don of Tallahassee
*See my VMS deconstruction scheme for the rules for what parts are where in Voynich words and how to differentiate the parts in each word by following the deconstruction sequence.