[Text] word starting [q] must have a valid counterpart word starting [o]

[davidjackson]

Get an average number based on different transcriptions. We know what we need so it's fairly easy to run the numbers across different transcriptions.
The scenario is q+[?^o] versus q+o.

Now, we don't know the percentage of writing errors  as nick pointed out recently. Ideally we should have all q+[?^o] options regularised in Eva so we can analyse them and discard transcription errors 

What I would like is to be able to discard the motion that this is a fixed bigraph.