(31-03-2018, 07:51 PM)davidjackson wrote: You are not allowed to view links. Register or Login to view....
Emma suggests :
Quote:words beginning with [q] have two particular relationships. The first is that a word starting [q] must have a valid counterpart word starting [o], and it is not enough for the plain word without either [q] or [o] to exist. Conversely, even if the [o] form exists, that does not mean that the [q] form will....
I'll have to vote "no" but I'll wait a couple of days to be sure I understand the question correctly.
Some examples of q- tokens with no o counterparts:
f29r:2:5:1 qokShe but no counterpart okShe.
f51r:1:9:7 qoetam but no counterpart oetam.
f76r:1:8:2 qotedShedy but no counterpart otedShedy. (In the ms. it is definitely written as one token.)
f76r:1:9:4 qeTheed but no counterpart oeTheed.
f80r:1:1:3 qopolkain but no counterpart opolkain. (Note: this may be a rare curve-glyph rather than an "o" but even if it is, there's no counterpart.)
f102r1:2:4:6 qokeodol but no counterpart okeodol.
There are many plain words that occur without q- or o- counterparts, so I'm not sure I correctly understand this part of the statement.
Quick examples from a single folio:
f66b:1:1:6 plain word dorShepy exists without odorShepy counterpart.
f66v:2:1:9 plain word Sheopam exists without oSheopam counterpart.
f66v:3:4:10 plain word chkchody exists without ochkchody counterpart.

