At the moment, I think I can fully compare the text of You are not allowed to view links.
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anchiton oladabad miltod tc cetr ceve portad m
six marix morix vix ahta ma ria
arorsheey paldcn ubreƞ so nim gas mich
pchedar qokaiin qotaiin dl ral cheodl cphaiin daiin ar
qekeeey qoparaiin olcheear chedar or
arorsheey olkeechy or char cheeol s or or aiin otam
(enlarged to make the colored text easier to read)
1). The parts of the words oladaba
d and porta
d correspond to the Voynich glyphs
iin d. So,
iin, in, or
n can be the letter a!
2). In my opinion, the spell about Maria is not consistent. At first, the author mistakenly wrote the letter m, which may correspond to
ar (by the way, the word anchiton may be the same as michiton, given this coincidence. The word
pchedar also contains
ar). Secondly, I have problems with establishing the correspondence of parts of words, but it seems to exist: the digram
ar and m occur 3 times, respectively (not counting the upper
ar). The letter
n appears once in the second row and twice if we count the upper
aiin. If we assume that y is equal to n (which is actually possible, as I mentioned in You are not allowed to view links.
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Login to view., but in this case it is an assumption), we can increase the maximum number to four. However, there is no room for the last a in the word maria. It is possible that maria is an attempt to correct the word marix. Possible values:
e or
ee = i.
3). The word pal
dcn does not fit in the third row because it does not have a
d. However, it may be related to the word
olkeechy if
y = a. It could just be a failed attempt at decryption.
4). ar occurs 1 time, and the letter m in the passage "so nim gas mich" occurs twice. It is possible that the word
char is actually mich. (these same letters are found in
pchedar -
michiton. This is similar to the anagrams I also mentioned in my thread). The letter
n appears in the passage once, and the letter a appears accordingly. I have written ubreƞ in the same passage for completeness, because it may be hidden among the unsolved letters.
5). Most likely, tc cetr ceve is an unsuccessful decryption of some word. Outwardly, it resembles the fact that the author incorrectly applied his alphabets (or something else?) and got first tc, then cetr, then ceve, and then realized that he was mistaken. There is no place for these words in the text.
6). Regarding milto
d, I would like to point out that the letter m could be
ra. But it's not a fact...
What do I think? There are two versions here:
1). If this is the transcription of an enthusiast who is not related to the author of VMS, then his methods of transcription were probably focused on a German-language result. He didn't know how to spell
d. He may have had two alphabets, although the matches are stable (bigram/letter-Latin letter). Apparently, the decryption principle was based on substitution (possibly even based on Roman numerals!). An unusual coincidence for me was
n = a. If n is the Roman I, then this fits a, which is the first letter of the Latin alphabet. He probably added i wherever he thought it was necessary (thus, mch became mich; although it makes sense for German that
ch = ich).
It's not certain that this decoding is correct...
2). If this decryption is made by a person who has received a recommendation from the author or knows something about the encryption method, it may indicate that the text is indeed an anagram. For example, in the words
char (mich) and
pchedar (michiton), the letters ch and ar are in the same order at the beginning and end, and they are also decrypted in the same order, but in reverse.
The person who deciphered it probably didn't know enough to get a complete and meaningful result, except for so nim gas mich (this part, in my opinion, falls on
char cheeol s or or, which are mostly separate letters. It was probably easier to work with them).
We can try to fish out hints:
n = a
y = a?
ch = ich/ch
e or
ee = i
ar = m
However, I'm inclined to believe that this is someone's not-so-successful attempt at decryption. This is the best explanation for the features I have described.
